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JEE PHYSICS MCQ: GRAVITATION

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Application +4 | -1

The imaginary angular velocity of the earth for which the effective acceleration due to gravity at the equator shall be zero is equal to
(Take,

g=10 \mathrm{~ms}^{-2}

for the acceleration due to gravity, if the earth were at rest, radius of earth equal to

6400 \mathrm{~km}

and

\lambda=60

)

View answer and explanation

Correct option: B

2.50 \times 10^{-3} \mathrm{~rad} \mathrm{~s}^{-1}

Option B (

2.50 \times 10^{-3} \mathrm{~rad} \mathrm{~s}^{-1}

) is correct because it is derived from setting the effective gravity at the equator to zero and solving for the angular velocity.

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