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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Application +4 | -1
The value of 12!+23!+...+9991000!\frac{1}{{2!}} + \frac{2}{{3!}} + ... + \frac{{999}}{{1000!}} is equal to
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Correct option: A
1000!−11000!\frac{{1000! - 1}}{{1000!}}
Option A (1000!−11000!\frac{{1000! - 1}}{{1000!}}) is correct because the series telescopes, leaving only the first term and the negative of the last term.

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