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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Analyzing +4 | -1
Let SnS_n denote the sum of the cubes of the first nn natural numbers and sns_n denote the sum of the first nn natural numbers. Then, āˆ‘r=1nSrsr\sum\limits_{r=1}^n \frac{S_r}{s_r} is equal to
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Correct option: C
(n+23)āˆ‘r=1nr\left(\frac{n+2}{3}\right) \sum\limits_{r=1}^n r
Option C ((n+23)āˆ‘r=1nr\left(\frac{n+2}{3}\right) \sum\limits_{r=1}^n r) is correct because it is the simplified form of the sum of the series.

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