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JEE PHYSICS MCQ: CURRENT ELECTRICITY

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In a metre bridge the balancing point is found to be at 39.5 cm39.5 \mathrm{~cm} from A\mathrm{A}, when the resistor Y=12.5Ω\mathrm{Y}=12.5 \Omega. The value of X\mathrm{X} is
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Correct option: A
8.16Ω8.16 \Omega
Option A (8.16Ω8.16 \Omega) is correct because it is calculated using the Wheatstone bridge principle, where the ratio of resistances is equal to the ratio of lengths.

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