Arrange the following monomers in order of decreasing ability to undergo cationic polymerisation ${\rm{I}}{\rm{.}}\,\,\,\,\,{\rm{N}}{{\rm{O}}_2}{{\rm{C}}_6}{{\rm{H}}_5} - {\rm{CH}} = {\rm{C}}{{\rm{H}}_2}$ ${\rm{II}}{\rm{.}}\,\,\,\,\,{\rm{C}}{{\rm{H}}_2} = {\rm{CH}} - {{\rm{C}}_6}{{\rm{H}}_5}{\rm{C}}{{\rm{H}}_3}$ ${\rm{III}}{\rm{.}}\,\,\,\,\,{\rm{C}}{{\rm{H}}_2} = {\rm{CH}} - {{\rm{C}}_6}{{\rm{H}}_5}{\rm{OC}}{{\rm{H}}_3}$

JEE CHEMISTRY MCQ: POLYMERS

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Arrange the following monomers in order of decreasing ability to undergo cationic polymerisation

\mathrm{I}\mathrm{.}\,\,\,\,\,\mathrm{N}{\mathrm{O}_2}{\mathrm{C}_6}{\mathrm{H}_5} - \mathrm{CH} = \mathrm{C}{\mathrm{H}_2}

\mathrm{II}\mathrm{.}\,\,\,\,\,\mathrm{C}{\mathrm{H}_2} = \mathrm{CH} - {\mathrm{C}_6}{\mathrm{H}_5}\mathrm{C}{\mathrm{H}_3}

\mathrm{III}\mathrm{.}\,\,\,\,\,\mathrm{C}{\mathrm{H}_2} = \mathrm{CH} - {\mathrm{C}_6}{\mathrm{H}_5}\mathrm{OC}{\mathrm{H}_3}

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Correct option: B

III > II > I

Option B is correct because electron-releasing groups activate the monomer towards cationic polymerization.