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JEE MATHEMATICS MCQ: ELLIPSE

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If the normals to

\frac{x^2}{a^2}+\frac{y^2}{b^2}=1

at the ends of the chords

l_1 x+m_1 y=1

and

l_2 x+m_2 y=1

are concurrent, then

View answer and explanation

Correct option: B

a^2 l_1 l_2=b^2 m_1 m_2=-1

Option B is correct because it represents the condition for concurrency of normals at the ends of the given chords.

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\frac{x^2}{144}+\frac{y^2}{81}=1

be the equation of an ellipse. If

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be the maximum distance of the centre of the ellipse from the normal, then the value of

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\frac{{{x^2}}}{{25}} + \frac{{{y^2}}}{{16}} = 1

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S'.

A

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9 x^{2}+16 y^{2}=144

\mathrm{PA}+\mathrm{PB}

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The slope of a common tangent to the ellipse

\frac{x^2}{a^2}+\frac{y^2}{b^2}=1

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r

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\frac{x^2}{25}+\frac{y^2}{16}=1

P

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Q

R

be the image of

Q

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N P

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O