JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy

1 of 1

Application +4 | -1

The sum of

n

terms of

{m}\, {A.P.s}

are

{S}_1, {~S}_2, {~S}_3, \ldots, {S}_{{m}}

. If the first term and common difference are

1,2,3, \ldots, m

respectively, then

{S}_1+{S}_2+{S}_3+\ldots+{S}_{{m}}=

View answer and explanation

Correct option: A

\frac{1}{4}\, m n(m+1)(n+1)

Option A (

\frac{{1}}{{4}} m n(m+1)(n+1)

) is correct because it represents the sum of

n

terms of

m

arithmetic progressions with given first terms and common differences.

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