The density of $3 \mathrm{M}$ solution of $\mathrm{NaCl}$ is $1.25 \mathrm{~g} \mathrm{~mL}^{-1}$. Calculate the molality of the solution.

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JEE CHEMISTRY MCQ: SOME BASIC CONCEPTS OF CHEMISTRY

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The density of

3 \mathrm{M}

solution of

\mathrm{NaCl}

1.25 \mathrm{~g} \mathrm{~mL}^{-1}

. Calculate the molality of the solution.

View answer and explanation

Correct option: A

2.79 m

Option A (2.79 m) is correct because molality is calculated by dividing the moles of solute by the mass of the solvent in kg, considering the density of the solution.

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