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JEE PHYSICS MCQ: WAVE OPTICS

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Light of wavelength

6000 ~\mathop {\text{A}}\limits^ \circ

is incident normally on a single slit of width

24 \times 10^{-5} \mathrm{~cm}

. Find out the angular position of second minimum from central maxima?

View answer and explanation

Correct option: B

30^{\circ}

Option B (

30^{\circ}

) is correct because it is calculated using the formula for the angular position of the second minimum in a single-slit diffraction pattern.

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