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JEE MATHEMATICS MCQ: LIMITS

1 Easy
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Analyzing +4 | -1
The value of lim⁡x→0x2sin⁡(1x)sin⁡x\lim\limits_{x \to 0} \frac{{{x^2}\sin \left( {\frac{1}{x}} \right)}}{{\sin x}}, is
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Correct option: B
0
Option B (0) is correct because the product of a function approaching zero and a bounded function is zero.

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