JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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Application +4 | -1

\cos x-\frac{\cot \beta \sin x}{2}=\frac{\sqrt{3}}{2}

, then the value of

\tan \frac{x}{2}

View answer and explanation

Correct option: A

\tan \frac{\beta}{2} \tan 15^{\circ}

Option A (

\tan \frac{\beta}{2} \tan 15^{\circ}

) is correct because it is derived by solving the given trigonometric equation for

\tan \frac{x}{2}

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