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NEET UG PHYSICS MCQ: WORK-ENERGY-POWER

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Application +4 | -1
A particle experiences a variable force F⃗=(2x2i^+2yj^)N\vec{F}=\left(2 x^2 \hat{i}+2 y \hat{j}\right) N in a horizontal X−YX-Y plane. where xx and yy are in meters. If the particle moves from point (0,1)(0,1) to point (1,2)(1,2) in the X−YX-Y plane, then kinetic energy charges by
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Correct option: A
113 J\frac{11}{3} \mathrm{~J}
Option A (113 J\frac{11}{3} \mathrm{~J}) is correct because the change in kinetic energy is equal to the work done by the force, which is calculated by integrating the force along the path.

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