The unit of expression ${{\rm{\mu }}_0}{{\rm{\varepsilon }}_0}$ are

${{\rm{s}}^2}{{\rm{m}}^{ - 2}}$

${{\rm{m}}^2}{{\rm{s}}^{ - 2}}$

JEE PHYSICS MCQ: UNITS & MEASUREMENTS

1 Easy

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Understanding +4 | -1

The unit of expression

{\mathrm{\mu }_0}{\mathrm{\varepsilon }_0}

are

View answer and explanation

Correct option: C

{\mathrm{s}^2}{\mathrm{m}^{ - 2}}

Option C (

{\mathrm{s}^2}{\mathrm{m}^{ - 2}}

) is correct because

{\mathrm{\mu }_0}{\mathrm{\varepsilon }_0}

is the reciprocal of the speed of light squared.

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