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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Analyzing +4 | -1
The sum to nn terms of the series 1+2(1+1n)+3(1+1n)2+…1+2\left(1+\frac{1}{n}\right)+3\left(1+\frac{1}{n}\right)^2+\ldots, is given by
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Correct option: A
n2n^2
Option A (n2n^2) is correct because the summation of the given series results in n2n^2 after simplification.

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