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JEE MATHEMATICS MCQ: RATE MEASURE

1 Easy
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Application +4 | -1
The distance covered by a particle in tt second is given by x=3+8t−4t2.  x = 3 + 8t - 4{t^2}.\; After 1s its velocity will be
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Correct option: A
0 unit
Option A (0 unit) is correct because the velocity after 1 second is calculated by differentiating the position function and substituting t=1.

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