If $\tan \,\,\frac{x}{2} = {\rm{cosec}}\;\,\,x - \sin \,\,x$, then the value of ${\tan ^2}\,\,\frac{x}{2}$, is

JEE MATHEMATICS MCQ: MULTIPLE AND SUBMULTIPLE ANGLES

1 Easy

1 of 1

Analyzing +4 | -1

\tan \,\,\frac{x}{2} = \mathrm{cosec}\;\,\,x - \sin \,\,x

, then the value of

{\tan ^2}\,\,\frac{x}{2}

, is

View answer and explanation

Correct option: D

- \,2 + \sqrt 5

Option D (

-2 + \sqrt{5}

) is correct because solving the trigonometric equation for

\tan^2 \frac{x}{2}

leads to the value

-2 + \sqrt{5}

Practice All Chapter MCQs →

1 + \cos \,\,x = k

x

\sin \,\,\frac{x}{2}

\sin 12^\circ \cdot \sin 48^\circ \cdot \sin 54^\circ =

\alpha ,\;\,\,\beta \left( {\alpha \ne \beta } \right)

a\,\,\cos \,\,\theta + b\,\,\sin \,\,\theta = c

\tan \,\,\left( {\frac{{\alpha + \beta }}{2}} \right)

{\cos ^4}\theta - {\sin ^4}\theta

\cos ^{2} 10^{\circ}-\cos 10^{\circ} \cos 50^{\circ}+\cos ^{2} 50^{\circ}

\triangle P Q R, \angle R=\frac{\pi}{2}

\tan \left(\frac{P}{2}\right)

\tan \left(\frac{Q}{2}\right)

a x^2+b x+c=0, a \neq 0