If $f\left( a \right) = 2,f'\left( a \right) = 1,g\left( a \right) = - 1,g'\left( a \right) = 2$, then the value of $\mathop {\lim }\limits_{x \to a} \frac{{g\left( x \right)f\left( a \right) - g\left( a \right)f\left( x \right)}}{{x - a}}$, is

JEE MATHEMATICS MCQ: LIMITS

1 Easy

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Application +4 | -1

f\left( a \right) = 2,f'\left( a \right) = 1,g\left( a \right) = - 1,g'\left( a \right) = 2

, then the value of

\lim\limits_{x \to a} \frac{{g\left( x \right)f\left( a \right) - g\left( a \right)f\left( x \right)}}{{x - a}}

, is

View answer and explanation

Correct option: C

Option A (-28) is correct because by applying L'Hopital's rule, the limit can be evaluated to -28.