JEE MATHEMATICS MCQ: MEAN VALUES THEOREM

1 Easy

1 of 1

Application +4 | -1

2 a+3 b+6 c=0,

then the equation

a x^2+b x+c=0

has in the interval

(0,1)

View answer and explanation

Correct option: A

At least one root

The correct answer is A (At least one root) because applying Rolle's theorem to the function

f(x)

guarantees the existence of at least one root in the interval (0, 1).

More Questions from MEAN VALUES THEOREM

Practice All Chapter MCQs →

f(x)

g(x)

[0,1]

f(0)=2, f(1)=6, g(0)=0, g(1)=

0 < \mathrm{c} < 1

f(x)

f(x)

f(x)=|\sin | x ||

\left[-\frac{\pi}{3}, \frac{\pi}{3}\right]

f\left( x \right) = \sqrt {x - 1} + \sqrt {x + 24 - 10\sqrt {x - 1} } ,\;1 \le x \le 26

f'\left( x \right)

1 < x < 26

- 1 \le x \le 1

f(x)

[3,5]

\int\limits_3^5 {f\left( x \right)} \,dx

\frac{{f\left( b \right) - f\left( a \right)}}{{b - a}} = f'\left( c \right)

f\left( x \right) = x\left( {x - 1} \right)\left( {x - 2} \right)