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JEE MATHEMATICS MCQ: PERMUTATIONS

1 Easy

1 of 1

Application +4 | -1

If

x \in {N}

and

\frac{(2 x) !}{3 !(2 x-3) !}: \frac{x !}{2 !(x-2)}=44: 3

, then

x

is equal to

View answer and explanation

Correct option: A

6

Option A (6) is correct because solving the given ratio of permutations leads to the equation 2x-1=11, which gives x=6.

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