JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy

1 of 1

Application +4 | -1

The set of real values of

x

satisfying ||

x-1|-1| \mid \leq 1

View answer and explanation

Correct option: A

[-1,3]

The correct answer is A ([-1,3]) because the solution set is found by solving the nested absolute value inequality.

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A=\{1,2,3\}, B=\{3,4\}, C=\{4,5,6\}

{A} \cup({B} \cap {C})

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{x^2},{b^2},{y^2}

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y

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y=x-2

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\log \left(\frac{a}{3 b}\right)

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\frac{3}{4}