JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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\frac{{\frac{1}{2}.\frac{2}{2}}}{{{1^3}}} + \frac{{\frac{2}{2}.\frac{3}{2}}}{{{1^3} + {2^3}}} + \frac{{\frac{3}{2}.\frac{4}{2}}}{{{1^3} + {2^3} + {3^3}}} + ... + n

terms equals

View answer and explanation

Correct option: C

\left( {\frac{n}{{n + 1}}} \right)

Option C

\left( {\frac{{n}}{{n + 1}}} \right)

is the correct answer because the series simplifies to a telescoping series, resulting in the given expression.

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