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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Analyzing +4 | -1
If 1e3x(ex+e5x)=a0+a1x+a2x2+…\frac{1}{{{e^{3x}}}}\left( {{e^x} + {e^{5x}}} \right) = {a_0} + {a_1}x + {a_2}{x^2} + \ldots, then 2a1+23a3+25a5+…2{a_1} + {2^3}{a_3} + {2^5}{a_5} + \ldots is equal to
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Correct option: D
0
Option D (0) is correct because when the given expression is simplified, the coefficients of the odd powers of x are zero, resulting in the sum being zero.

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