Let $X = \left[ {\begin{array}{*{20}{c}} {{x_1}}\\ {{x_2}}\\ {{x_3}} \end{array}} \right],\;A = \left[ {\begin{array}{*{20}{c}} 1&{ - 1}&2\\ 2&0&1\\ 3&2&1 \end{array}} \right]$ and $B = \left[ {\begin{array}{*{20}{c}} 3\\ 1\\ 4 \end{array}} \right]$. If $AX = B$, then $X$ is equal to

$\left[ {\begin{array}{*{20}{c}} { - 1}\\ 2\\ 3 \end{array}} \right]$

$\left[ {\begin{array}{*{20}{c}} 1\\ 2\\ 3 \end{array}} \right]$

$\left[ {\begin{array}{*{20}{c}} { - 1}\\ { - 2}\\ 3 \end{array}} \right]$

$\left[ {\begin{array}{*{20}{c}} { - 1}\\ { - 2}\\ { - 3} \end{array}} \right]$

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JEE MATHEMATICS MCQ: MATRICES

1 Easy

1 of 1

Application +4 | -1

Let

X = \left[ {\begin{array}{cccccccccccccccccccc} {{x_1}}\\ {{x_2}}\\ {{x_3}} \end{array}} \right],\;A = \left[ {\begin{array}{cccccccccccccccccccc} 1&{ - 1}&2\\ 2&0&1\\ 3&2&1 \end{array}} \right]

and

B = \left[ {\begin{array}{cccccccccccccccccccc} 3\\ 1\\ 4 \end{array}} \right]

. If

AX = B

, then

X

is equal to

View answer and explanation

Correct option: D

\left[ {\begin{array}{cccccccccccccccccccc} { - 1}\\ 2\\ 3 \end{array}} \right]

Option D ([-1], [2], [3]) is correct because it is the solution to the matrix equation AX = B, obtained by finding the inverse of A and multiplying it by B.

JEE MATHEMATICS MCQ: MATRICES

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