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JEE PHYSICS MCQ: THERMODYNAMICS

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Application +4 | -1
The relation between energy UU, pressure PP and volume VV for an ideal gas in an adiabatic process is given by, relation U=a+bPVU=a+b P V. Find the value of adiabatic exponent (γ)(\gamma) of this gas.
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Correct option: A
b+1b\frac{b+1}{b}
Option A (b+1b\frac{b+1}{b}) is correct because it is derived by comparing the given relation with the adiabatic process equation and solving for the adiabatic exponent.

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