A thermodynamical system is changed from state$\left( {{p_1}{V_1}} \right){\rm{to}}\left( {{p_2},{V_2}} \right)$ by two different processes, the quantity which will remain same will be

${\rm{\Delta }}Q - {\rm{\Delta }}W$

${\rm{\Delta }}Q + {\rm{\Delta }}W$

NEET UG PHYSICS MCQ: THERMODYNAMICS

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A thermodynamical system is changed from state

\left( {{p_1}{V_1}} \right)\mathrm{to}\left( {{p_2},{V_2}} \right)

by two different processes, the quantity which will remain same will be

View answer and explanation

Correct option: D

\mathrm{\Delta }Q - \mathrm{\Delta }W

Option D (

\mathrm{\Delta }Q - \mathrm{\Delta }W

) is correct because the change in internal energy, which is a state function, is equal to

\mathrm{\Delta }Q - \mathrm{\Delta }W

according to the first law of thermodynamics.