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JEE MATHEMATICS MCQ: STATISTICS

1 Easy

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Application +4 | -1

The mean and variance of the data 4, 5, 6, 6, 7, 8,

x,y,

where

x < y,

are 6 and

\frac{9}{4}

respectively. Then

{x^4} + {y^2}

is equal to

View answer and explanation

Correct option: B

320

Option B (320) is correct because after solving for x and y using the given mean and variance,

{x^4} + {y^2}

is calculated to be 320.

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