JEE PHYSICS MCQ: UNITS & MEASUREMENTS

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Application +4 | -1

\frac{{E}^2}{\mu_0}

has the dimensions (

{E}=

electric field,

\mu_0=

permeability of free space)

View answer and explanation

Correct option: B

\left[{MLT}^{-4}\right]

Option B ([

{MLT}^{-4}

]) is correct because it represents the dimensions of energy density divided by the square of speed of light.

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