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NEET UG PHYSICS MCQ: MAGNETIC EFFECT OF CURRENT

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The oscillating magnetic field in a plane electromagnetic wave is given by By=5×10−6sin⁡1000π(5x−4×108t)TB_y=5 \times 10^{-6} \sin 1000 \pi\left(5 x-4 \times 10^8 t\right) \mathrm{T} The amplitude of electric field will be:
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Correct option: D
4×102Vm−14 \times 10^2 \mathrm{Vm}^{-1}
Option D (4×102Vm−14 \times 10^2 \mathrm{Vm}^{-1}) is correct because the amplitude of the electric field is calculated using the relationship E = cB, where c is the speed of light and B is the magnetic field amplitude.

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