NEET UG PHYSICS MCQ: ELECTROMAGNETIC WAVES

1 Easy

1 of 1

Application +4 | -1

If frequency of electromagnetic wave is

60 \mathrm{~MHz}

and it travels in air along

z

direction then the corresponding electric and magnetic field vectors will be mutually perpendicular to each other and the wavelength of the wave (in

\mathrm{m}

) is

View answer and explanation

Correct option: D

Option D (5) is correct because the wavelength is calculated using the formula

\lambda = c/f

, where

c

is the speed of light and

f

is the frequency.

More Questions from ELECTROMAGNETIC WAVES

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{E_X}

{E_R}

{E_M}

60\,\,\frac{V}{m}

{E_1} = {E_{01}}\hat x\cos \left[ {2\pi v\left( {\frac{z}{c} - t} \right)} \right]

{E_2} = {E_{02}}\hat x\cos \left[ {k\left( {2z - ct} \right)} \right]

{\varepsilon _{{r_1}}}

{\varepsilon _{{r_2}}}

E = 50\sin \,(500x - 10 \times {10^{10}}t)\,v/m.

c

\mathrm{\varepsilon }

\mathrm{\mu }

\sqrt {\frac{\mathrm{\mu }}{\mathrm{\varepsilon }}}