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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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If ∫01e−x2dx=a\int\limits_{0}^1 e^{-x^2} d x=a, then ∫01x2e−x2dx\int\limits_{0}^1 x^2 e^{-x^2} d x is equal to
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Correct option: A
12e(ea−1)\frac{1}{2 e}(e a-1)
Option A (12e(ea−1)\frac{1}{{2e}}(ea - 1)) is correct because using integration by parts, the integral ∫01x2e−x2dx\int_0^1 x^2 e^{-x^2} dx can be expressed in terms of ∫01e−x2dx=a\int_0^1 e^{-x^2} dx = a.

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