JEE MATHEMATICS MCQ: LIMITS

1 Easy

1 of 1

Analyzing +4 | -1

\lim \limits_{{x \rightarrow 0}} \frac{\left(1-e^x\right) \sin x}{x^2+x^3}

is equal to

View answer and explanation

Correct option: A

-1

Option A (-1) is correct because the limit is evaluated using standard limit results, resulting in -1.

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\lim \limits_{{x \rightarrow 0}}\left(\frac{1}{x^2}-\operatorname{cosec}^2 x\right)

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