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JEE MATHEMATICS MCQ: LIMITS

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Application +4 | -1
Let f(x)f(x) be a differentiable function at x=a,x=a, f1(a)=4,f^1(a)=4, f(a)=2.f(a)=2. Then lim⁡x→axf(a)−af(x)x−a\lim \limits_{{x \rightarrow a}} \frac{x f(a)-a f(x)}{x-a} is equal to
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Correct option: B
2−4a2-4 a
Option B (2−4a2-4a) is correct because applying L'Hopital's rule and using the given values of f(a)f(a) and f′(a)f'(a) leads to this result.

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