JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Easy

1 of 1

Application +4 | -1

\int\limits_{0}^{\pi / 2} \max (\sin x, \cos x) d x

is equal to

View answer and explanation

Correct option: D

\sqrt{2}

Option D (

\sqrt{{2}}

) is correct because the integral

\int_0^{\pi/2} \max(\sin x, \cos x) dx

can be split into two integrals based on where

\sin x > \cos x

and vice versa, and the result is

\sqrt{{2}}

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