JEE MATHEMATICS MCQ: TANGENTS & NORMALS

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Analyzing +4 | -1

The coordinates of a point on the curve

x=4 t^2+3, y=8 t^3-1

such that the tangent to the curve at that point is normal to the curve at its other intersection point with the curve, are

View answer and explanation

Correct option: A

\left(\frac{35}{9}, \pm \frac{16 \sqrt{2}}{27}-1\right)

Option A (

\left(\frac{{35}}{{9}}, \pm \frac{{16 \sqrt{{2}}}}{{27}}-1\right)

) is correct because it satisfies the condition where the tangent at one point is normal at another point on the curve.

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\mathrm{C}

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\theta = \left( {2k + 1} \right)\pi ,\;k \in Z