JEE PHYSICS MCQ: SYSTEM OF PARTICLES

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Analyzing +4 | -1

An equilateral triangle

A B C

formed from a uniform wire has two small identical beads initially located at

A

. The triangle is set rotating about the vertical axis

A O

. Then the beads are released from rest simultaneously and allowed to slide down, one along

A B

and the other along

A C

as shown. Neglecting frictional effects, the quantities that are conserved as the beads slide down, are

View answer and explanation

Correct option: B

total angular momentum and total energy

Option B (total angular momentum and total energy) is correct because no external torque acts on the system and energy is conserved due to the absence of friction.

More Questions from SYSTEM OF PARTICLES

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It is easier for a swimmer jumping into water from a height to describe a loop in the air by A uniform thin rod

\mathrm{AB}

of length

\mathrm{L}

has linear mass density

\mu(x)=a+\frac{b x}{L}

, where

x

is measured from

\mathrm{A}

. If the

\mathrm{CM}

of the rod lies at a distance of

\left(\frac{7}{12}\right) \mathrm{L}

from

\mathrm{A}

, then a and

\mathrm{b}

1.0 \mathrm{~g}

is rotating in a circle of diameter

8 \mathrm{~cm}

. Its moment of inertia will be The angular velocity of a particle is given by

\omega = {t^4} + 2{t^3}

then its angular acceleration of the particle at

t = 1\,sec

\left( {rad\,{s^{ - 2}}} \right)