JEE CHEMISTRY MCQ: CHEMICAL KINETICS

1 Hard

1 of 1

Analyzing +4 | -1

The reaction of

(+)

2-iodobutane and

\mathrm{NaI}^*

(

\mathrm{I}^*

is radioactive isotope of iodine) in acetone was studied by measuring the rate of racemization

\left(\mathrm{k}_{\mathrm{r}}\right)

and the rate of inversion

\left(\mathrm{k}_{\mathrm{i}}\right)

(+) \mathrm{CH}_3 \mathrm{CH}(\mathrm{I}) \mathrm{CH}_2 \mathrm{CH}_3+\mathrm{NaI}^* \rightarrow \mathrm{CH}_3 \mathrm{CH}\left(\mathrm{I}^*\right) \mathrm{CH}_2 \mathrm{CH}_3+\mathrm{NaI}

For this reaction, the relationship between

\mathrm{k}_{\mathrm{r}}

and

\mathrm{k}_{\mathrm{i}}

View answer and explanation

Correct option: B

\mathrm{k}_{\mathrm{i}}=0.5 \mathrm{k}_{\mathrm{r}}

Option B (

\mathrm{k}_{\mathrm{i}}=0.5 \mathrm{k}_{\mathrm{r}}

) is correct because the rate of racemization is twice the rate of inversion in this SN1 reaction.

More Questions from CHEMICAL KINETICS

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\mathrm{A}_2+\mathrm{B}_2 \rightarrow 2 \mathrm{AB}

\begin{aligned} & {{\text{A}}_2}\mathop \rightleftharpoons \limits_{{{\text{k}}_{ - 1}}}^{{{\text{k}}_1}} {\text{A}} + {\text{A (fast) }} \\ & \mathrm{A}+\mathrm{B}_2 \xrightarrow{\mathrm{k}_2} \mathrm{AB}+\mathrm{B} \text { (slow) } \\ & \mathrm{A}+\mathrm{B} \rightarrow \mathrm{AB} \text { (fast) } \end{aligned}

k

(Initial\mathrm{ }conc.\mathrm{ } = a)

C_0 \sqrt{T}

C_0

T

100 \mathrm{~kJ/mol}.

75 \%

\log _{10} \frac{K_2}{K_1}

27^{\circ} \mathrm{C}

2.303 \times 8.314=19.147