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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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If ∣a∣<1\left| a \right| < 1 and ∣b∣<1,\left| b \right| < 1, then the sum of the series a(a+b)+a2(a2+b2)+a3(a3+b3)+…a\left( {a + b} \right) + {a^2}\left( {{a^2} + {b^2}} \right) + {a^3}\left( {{a^3} + {b^3}} \right) + \ldots upto ∞\infty, is
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Correct option: B
a21−a2+ab1−ab\frac{{{a^2}}}{{1 - {a^2}}} + \frac{{ab}}{{1 - ab}}
Option B (a21−a2+ab1−ab\frac{{{a^2}}}{{1 - {a^2}}} + \frac{{ab}}{{1 - ab}}) is correct because the series can be split into two geometric series, and their sums can be calculated.

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