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JEE PHYSICS MCQ: WAVES

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Application +4 | -1
Two tuning fork P  and  QP\,\,and\,\,\mathrm{Q} when set vibrating give 4   beats/s4{\mkern 1mu} {\mkern 1mu} \,beats/s. if a prong of the fork PP is filed the beats are reduced to 2  s−12\,\,{s^{ - 1}}. What is frequency of PP, if that of QQ is 250  Hz250\,\,Hz?
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Correct option: A
246  Hz\begin{array}{llllllllllllllllllll} {246\,\,Hz} \end{array}
The correct answer is A (246 Hz) because filing a prong increases the frequency, and the beat frequency decreasing to 2 Hz implies the original frequency of P was lower than Q.

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