Acidic solution of ${{\rm{S}}_2}{\rm{O}}_3^{2 - }$ is converted to ……… in presence of ${{\rm{I}}_2}$

${{\rm{S}}_4}{\rm{O}}_6^{2 - } + {{\rm{I}}^ - }$

${\rm{SO}}_4^{2 - } + {{\rm{I}}^ - }$

${\rm{S}}{{\rm{O}}_3} + {{\rm{I}}^ - }$

${{\rm{S}}_4}{\rm{O}}_6^{2 - } + {\rm{I}}_3^ - $

NEET UG CHEMISTRY MCQ: P-BLOCK ELEMENTS

1 Hard

1 of 1

Understanding +4 | -1

Acidic solution of

{\mathrm{S}_2}\mathrm{O}_3^{2 - }

is converted to ……… in presence of

{\mathrm{I}_2}

View answer and explanation

Correct option: A

{\mathrm{S}_4}\mathrm{O}_6^{2 - } + {\mathrm{I}^ - }

Option A (

{S_4}{O_6}^{2-} + I^−

) is correct because thiosulfate ion is oxidized to tetrathionate ion by iodine in acidic solution.