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JEE CHEMISTRY MCQ: ALCOHOLS & PHENOLS & ETHERS

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The compound CH3CH2CH2Br\mathrm{C}{\mathrm{H}_3}\mathrm{C}{\mathrm{H}_2}\mathrm{C}{\mathrm{H}_2}\mathrm{Br} is converted into CH3CH2CH2OH\mathrm{C}{\mathrm{H}_3}\mathrm{C}{\mathrm{H}_2}\mathrm{C}{\mathrm{H}_2}\mathrm{OH} by:
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Correct option: D
Substitution
Option D (Substitution) is correct because the bromine atom in CH3CH2CH2Br\mathrm{C}{\mathrm{H}_3}\mathrm{C}{\mathrm{H}_2}\mathrm{C}{\mathrm{H}_2}\mathrm{Br} is replaced by a hydroxyl group (OH) to form CH3CH2CH2OH\mathrm{C}{\mathrm{H}_3}\mathrm{C}{\mathrm{H}_2}\mathrm{C}{\mathrm{H}_2}\mathrm{OH}.

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