One of the rectangular components of a velocity of $60\,\,km{h^{ - 1\,\,\,}}\,{\rm{is}}\,\,\,30\,\,km{h^{ - 1}}$ .The other rectangular component is

$30\,\sqrt 3 {\rm{\;km}}{{\rm{h}}^{ - 1}}$

$30\,{\rm{km}}{{\rm{h}}^{ - 1}}$

$30\,\sqrt {2{\rm{\;}}} {\rm{km}}{{\rm{h}}^{ - 1}}$

NEET UG PHYSICS MCQ: MOTION IN PLANE

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Application +4 | -1

One of the rectangular components of a velocity of 

60\,\,km{h^{ - 1\,\,\,}}\,\mathrm{is}\,\,\,30\,\,km{h^{ - 1}}

.The other rectangular component is

View answer and explanation

Correct option: B

30\,\sqrt 3 \mathrm{\;km}{\mathrm{h}^{ - 1}}

Option B (

30\sqrt 3 \;\mathrm{km}{\mathrm{h}^{ - 1}}

) is correct because it is calculated using the Pythagorean theorem, given one component and the resultant velocity.

Practice All Chapter MCQs →

\mathrm{\vec a}\,and\,\mathrm{\vec b}

\mathrm{\vec a}\,and\,\mathrm{\vec b}

\overrightarrow P \,\,.\,\,\overrightarrow Q = 0\,and\,\overrightarrow P \,\, \times \,\,\overrightarrow Q = 0

\overrightarrow Q \,and\,\overrightarrow R

\vec{A}=3 \hat{i}+4 \hat{j}

\vec{B}=6 \hat{i}+8 \hat{j}

A

B

\overrightarrow{\mathrm{A}}

\overrightarrow{\mathrm{B}}

{\cot ^{ - 1}}\left( 2 \right)