JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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One solution of the equation

4 \cos ^2 \theta \sin \theta-2 \sin ^2 \theta=3 \sin \theta

View answer and explanation

Correct option: A

\theta=n \pi+(-1)^n\left(\frac{-3 \pi}{10}\right)

Option A (

\theta=n \pi+(-1)^n\left(\frac{{-3 \pi}}{{10}}\right)

) is correct because by factoring the equation and solving for sin theta, we can find the general solution for theta.

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\mathrm{X}

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0 < x < \pi

\cos x+\sin x=\frac{1}{2}

\tan x