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JEE MATHEMATICS MCQ: PERMUTATIONS

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A seven-digit numbers divisible by 9 is to be formed by using 7 out of numbers {1,2,3,4,5,6,7,8,9}\{1,2,3,4,5, 6,7,8,9\}. The number of ways in which this can be done, is
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Correct option: D
4⋅7!4 \cdot 7!
Option D (4⋅7!4 \cdot 7!) is correct because there are 4 pairs of digits that can be excluded to make the sum of the remaining 7 digits divisible by 9, and each set of 7 digits can be arranged in 7! ways.

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