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JEE MATHEMATICS MCQ: PROBABILITY

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The probability of selecting integers a∈[−5,30] a \in \left[ { - 5,30} \right]\, such that x2+2(a+4)x−5a+64>0,{x^2} + 2\left( {a + 4} \right)x\mathrm{ } - \mathrm{ }5a\mathrm{ } + \mathrm{ }64\mathrm{ } > \mathrm{ }0,\mathrm{ } for all x∈R,x \in R, is
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Correct option: B
29\frac{2}{{9}}
Option B (29\frac{2}{{9}}) is correct because it represents the probability of 'a' lying within the interval (-16, 3) given the constraint a ∈ [-5, 30].

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