The focus of the parabola $y = 2{x^2} + x$ is

$\left( {\frac{1}{2},\frac{1}{4}} \right)$

$\left( { - \frac{1}{4},\frac{1}{8}} \right)$

JEE MATHEMATICS MCQ: PARABOLA

1 Easy

1 of 1

Application +4 | -1

The focus of the parabola

y = 2{x^2} + x

View answer and explanation

Correct option: C

\left( { - \frac{1}{4},0} \right)

Option D ((-

\frac{1}{4}

,0)) is correct because it represents the focus of the given parabola after completing the square and transforming the equation.

Practice All Chapter MCQs →

y=x^2

y=-(x-2)^2

P

y^2=16 x

P

P,Q,R

{y^2} = 4x

P

R

Q

PR

(1,0)

y^2+4 x=8

x^2=-16 y

I

{y^2} = 4ax

SP

SQ

PQ,S

SP,l

SQ