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NEET UG PHYSICS MCQ: OSCILLATIONS

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The maximum acceleration of a particle in SHM is made two times keeping the maximum speed to be constant. It is possible when
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Correct option: C
frequency is doubled while amplitude is halved
Option C (frequency is doubled while amplitude is halved) is correct because maximum acceleration amax=Aω2a_{max} = A\omega^2 and maximum speed vmax=Aωv_{max} = A\omega. If vmaxv_{max} is constant and amaxa_{max} is doubled, then A must be halved and ω must be doubled.

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