JEE MATHEMATICS MCQ: LIMITS

1 Easy

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Analyzing +4 | -1

\lim\limits_{x \to 0} \left\{ {\frac{1}{{x\sqrt[3]{{8 + x}}}} - \frac{1}{{2x}}} \right\}

is equal to

View answer and explanation

Correct option: D

\frac{{ - 1}}{{48}}

Option D (

\frac{{ - 1}}{{48}}

) is correct because it's the result of applying L'Hopital's rule or series expansion to evaluate the limit.

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