JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Easy

1 of 1

Application +4 | -1

\int {\frac{1}{x}\sqrt {\frac{{1 - x}}{{1 + x}}} dx = g\left( x \right) + c,\,\,g\left( 1 \right) = 0,}

then

g\left( {\frac{1}{2}} \right)

us equal to

View answer and explanation

Correct option: A

{\log _e}\left( {\frac{{\sqrt 3 - 1}}{{\sqrt 3 + 1}}} \right) + \frac{\pi }{3}

Option A (

{\log _e}\left( {\frac{{\sqrt 3 - 1}}{{\sqrt 3 + 1}}} \right) + \frac{\pi }{3}

) is correct because it is the result of the definite integral calculation with the given substitution and initial condition.

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