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JEE MATHEMATICS MCQ: PAIR OF STRAIGHT LINES

1 Easy
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Application +4 | -1
If the lengths of the perpendiculars drawn from origin to xsec⁡θ+ycosec⁡θ=ax \sec \theta+y \operatorname{cosec} \theta=a and xcos⁡θ−ysin⁡θ=acos⁡2θx \cos \theta-y \sin \theta=a \cos 2 \theta are pp and p′p^{\prime} respectively, then 4p2+p′2=……4 p^2+p^{\prime 2}=\ldots \ldots
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Correct option: A
a2a^2
Option A (a2a^2) is correct because the expression 4p2+p′24p^2 + p'^2 simplifies to a2a^2 using trigonometric identities.

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