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NEET UG PHYSICS MCQ: ELECTRO MAGNETIC INDUCTION

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Application +4 | -1

A coil of

100\,\,turns

and area

5\,\,square\,\,centimeter

is placed in a magnetic field

\mathrm{B} = 0.2\,\,T

. The normal to the plane of the coil makes an angle of

{60^0}

with the direction of the magnetic field. The magnetic flux linked with the coil is

View answer and explanation

Correct option: A

5 \times {10^{ - 3}}\,{\mkern 1mu} Wb

Option A (

5 \times {10^{ - 3}}\,{\mkern 1mu} Wb

) is correct because the magnetic flux is calculated using the formula

\phi = NBA \cos \theta

, where N is the number of turns, B is the magnetic field, A is the area, and

\theta

is the angle between the normal to the coil and the magnetic field.

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Assertion (A): Whenever the magnetic flux linked with a closed coil changes there will be an induced emf as well as an induced current.

Reason (R): According to Faraday, the induced emf is inversely proportional to the rate of change of magnetic flux linked with a coil. The coefficient of mutual inductance of two coils is

6\,\,mH

. If the current flowing in one is

2\,\,ampere

, then the induced e.m.f. in the second coil will be The induced emf cannot be produced by: Consider the statements:
(I)If magnetic field,

\mathrm{B = 0}

, then magnetic flux is also zero.
(II)If magnetic flux,

\phi = 0,

then magnetic field is also zero. The coefficient of self inductance of a solenoid is 0.18 mH. If a rod of soft iron of relative permeability 900 is inserted, then the coefficient of self inductance (in mH ) will become nearly: A uniformly wound solenoidal coil of self inductance

1.8 \times {10^{ - 4}}

H and resistance 6 Ω is broken up into two identical coils. These identical coils are then connected in parallel across a 12 V battery of negligible resistance. The time constant of the current in the circuit 